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17m=10m^2
We move all terms to the left:
17m-(10m^2)=0
determiningTheFunctionDomain -10m^2+17m=0
a = -10; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·(-10)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*-10}=\frac{-34}{-20} =1+7/10 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*-10}=\frac{0}{-20} =0 $
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